Question

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We have,

Natural number from $102$ to $113$

$=102,103,104,105,106,107,108,109,110,111,112,113$

Now, finding prime numbers

$103,107,109,113$

Divisible by $2$

Number ending with $2,4,6,8,0$ are divisible by $2$

So, $102,104,106,108,110,112$ are not prime.

Divisible by $3$

We know that, the sum of digits is divisible by $3,$

So, $105$ and $111$ are not prime

Then,$103,107,109,113$ are prime.

therefore, total number is$12$

prime number is $4$

Then,the fraction is $124 $.

Hence, this is the answer.

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